The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg / m3.

i. Calculate the increase in pressure as LR5 descends from the surface to a depth of 700m. (g=10m/s2)

Question

Kelley

Physics

11 March, 13:08

The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg / m3.

i. Calculate the increase in pressure as LR5 descends from the surface to a depth of 700m. (g=10m/s2)

+2

Answers (1)

Know the Answer?

Keira Roman · Answer 1

P = 7196 [kPa]

Explanation:

We can solve this problem using the expression that defines the pressure depending on the height of water column.

P = dens*g*h

where:

dens = 1028 [kg/m^3]

g = 10 [m/s^2]

h = 700 [m]

Therefore:

P = 1028*10*700

P = 7196000 [Pa]

P = 7196 [kPa]

The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg / m3.i. Calculate the increase in pressure as LR5 descends from the surface to a depth of 700m. (g=10m/s2)

The LR5 is the specialist submarine for underwater rescue. The average density of seawater is 1028 kg / m3.

i. Calculate the increase in pressure as LR5 descends from the surface to a depth of 700m. (g=10m/s2)