Calculate the quantity of energy produced per gram of reactant for the fusion of h-3 (atomic mass = 3.016049 amu) with h-1 (atomic mass = 1.007825 amu) to form he-4 (atomic mass = 4.002603 amu).

Question

Chanel Booth

Physics

25 June, 06:31

Calculate the quantity of energy produced per gram of reactant for the fusion of h-3 (atomic mass = 3.016049 amu) with h-1 (atomic mass = 1.007825 amu) to form he-4 (atomic mass = 4.002603 amu).

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Isiah Sweeney · Answer 1

The total mass of one atom of H-3 and H-1 is 4.02387 amu. The stated amu is 4.002603.

There is a mass difference because it is being converted into energy.

Mass difference is 0.021271 amu

If it is converted to equivalent to grams per mole.

Equal to 0.000021271 kg

By using the Einsteins equation, E = mc∧2.

Per mole is

E=0.000021271 * 299792458∧2J

E = 1.91174 * 10∧12 J per mole

The reactant of one mole is 4.02387 grams

The energy which is being released per gram of reactant is 4.751 * 10∧11J/g