What average mechanical power (in W) must a 70.5 kg mountain climber generate to climb to the summit of a hill of height 365 m in 49.0 min? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the power that must be produced by the climber's body. HINT

Question

Turbo

Physics

12 March, 22:49

What average mechanical power (in W) must a 70.5 kg mountain climber generate to climb to the summit of a hill of height 365 m in 49.0 min? Note: Due to inefficiencies in converting chemical energy to mechanical energy, the amount calculated here is only a fraction of the power that must be produced by the climber's body. HINT

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Flake · Answer 1

Work done by mountain climber against his weight

= mgH

= 70.5 X 9.8 X 365

= 252178.5 J

Power = work done / time taken to do work

= 252178.5 / (49 x 60)

= 85.775 J/s

= 85.775 W.