In a particular crash test, an automobile of mass 1692 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 20 m/s and 3 m/s, respectively. If the collision lasts for 0.16 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s.

I = - 3.89 104 N s

Explanation:

The impulse has two expressions on the one hand is equal to the product of force by time and on the other is equal to the moment variation of the system

I = ∫ F dt = Δp

Note that if the initial positive velocity the final one that has the opposite direction must be negative

Let's replace and calculate

I = mvf - mvo

I = 1692 (-3) - 1692 (20)

I = - 3.89 104 N s

[N s ] = [ kg m/s² s] = [ kg m/s]