Jake is bowling with a 8 kg bowling ball. He rolls the ball at 7 m/s, and it hits one stationary pin with a mass of 2 kg. The pin goes flying forward at 12 m/s. How fast is the bowling ball now traveling?

Question

Kasen Green

Physics

11 March, 08:34

Jake is bowling with a 8 kg bowling ball. He rolls the ball at 7 m/s, and it hits one stationary pin with a mass of 2 kg. The pin goes flying forward at 12 m/s. How fast is the bowling ball now traveling?

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Answers (1)

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Aedan Orozco · Answer 1

We know from the principle of conservation of momentum that the momentum of the system is conserved. The total momentum of the system is 8 kg x 7 m/s = 56 kg m/s. The momentum of the pin after getting hit is 24 kg m/s. So the momentum of the bowling ball after hitting the pin is 56 kg m/s - 24 kg m/s = 32 kg m/s

velocity of the ball is v = 32 kg m/s / 8 kg = 4 m/s