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10 September, 09:59

A rocket is fired at 100 m/s at an angle of 37, what was its total speed when it landed?

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  1. 10 September, 10:13
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    100 m/s

    Explanation:

    Let find the velocity components first

    Fx = 100 * cos (37) = 79.86 m/s

    Fy = 100 * sin (37) = 60.18 m/s

    applying motion equations

    Horizontal motion

    assuming no acceleration in horizontal direction we can assure that the ending velocity component will still remain Fx = 79.86 m/s

    Vertical motion (upwards)

    V² = U² + 2as

    = 60.18² + 2 * (-10) * 0

    Fy = 60.18 m/s

    Total speed = √ (F²x+F²y) = 100 m / s

    ** * You can take the same answer considering the Energy
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