The length of each of the bonds between the atoms of a molecule of nitrogen (n2) is 0.0465 nm. the mass of a nitrogen atom is 2.32 * 10-11 pg. determine the moment of inertia of the molecule about an axis passing through the center of mass perpendicular to the line joining the two atoms

Moment of inertia of N₂ molecule about an axis passing through the center of mass perpendicular to the line joining the two atoms=i=2.51 x 10⁻⁴⁷ kg m²

Explanation:

Moment of inertia = i = mr₁² + mr₂²

m = mass of nitrogen atom=2.32 x 10⁻¹¹pg=2.32 x 10⁻²⁶ Kg

r1 = r2=0.0465/2 = 0.02325 nm=2.325 x 10⁻¹¹ m

so i = 2.32 x 10⁻²⁶ (2.325 x 10⁻¹¹) ²+2.32 x 10⁻²⁶ (2.325 x 10⁻¹¹) ²

i=2.51 x 10⁻⁴⁷ kg m²