A piano emits frequencies that range from a low of about 28 hertz to a high of about 4200 hz. find the range of wavelength in air attained by this instrument when the speed of sound in air in 342m / s

The solution for this problem is:

A velocity of wave is given as V = λ⋅f

V - velocity of wave

f - frequency of wave

λ - wave length

So getting the wave length is:

λ = V/f

λminimum = V / fmaximum

λminimum = 342 / 4200

λminimum = 0.081 m

λmaximum = V / fminimum

λmaximum = 342 / 28

λmaximum = 12.214 m