Sue and Sean are having a tug-of-war by pulling on opposite ends of a 5.0-kg rope. Sue pulls with a 15-N force. What is Sean's force if the rope accelerates toward Sue at 2.0 m/s2?

Question

Matthew Mooney

Physics

6 March, 17:29

Sue and Sean are having a tug-of-war by pulling on opposite ends of a 5.0-kg rope. Sue pulls with a 15-N force. What is Sean's force if the rope accelerates toward Sue at 2.0 m/s2?

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Answers (1)

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Greta Morrow · Answer 1

5N

Explanation:

Sean's force is 5N because from the equation of Force, calculating for Sue's acceleration F=MA, A=F/M, A = 15N/5kg = 3m/s²

If Sue's force was 15N and he yielded 3m/s², If sean's accelerate towards Sue at 2m/s², his net acceleration of pull is 1m/s², therefore his force F=Ma = 5kg X 1m/s² + 5N