In a test of Upper H 0 : muequals100 against Upper H Subscript a : munot equals 100, the sample data yielded the test statistic z equals 2.24. Find the Upper P -value for the test.

The Answer is 0.0250

Explanation:

The null and alternative hypothesis is,

H0 : = 100

Ha : ≠100

Test statistic = z = 2.35

This is the two tailed test

P (Z > 2.24) = 1-P (Z < 2.24) = 1 - 0.9875 = 0.0125

P-value = 2 * P (Z > 2.24)

P-value = 2 * 0.0125

P-value = 0.0250