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17 November, 08:36

If the sum of a, b, and c, is twice the sum of a minus b and a minus c, then a =

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  1. 17 November, 08:44
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    A+b+c = 2 (-a - b - c) = = > a+b+c = - 2a - 2b - 2c==> a=-2a - 2b - 2c - b - c

    a+2a = - 3b - 3c = = > 3a = - 3b - 3c = = > a = - (b+c) / 3
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