Ask Question
30 July, 14:13

Sin2A + sin2B - sin2C = 4cosA*cosB*cosC

+2
Answers (2)
  1. 30 July, 14:21
    0
    Inconclusive

    Explanation:

    Sin2A = Sin (A+A) = SinACosA + CosAsinA=2SinACosA

    Similarly

    Sin2B = 2SinBCosB

    Sin2C=2SinCCosC

    Adding all; we cannot arrive at the expression at the right.
  2. 30 July, 14:26
    0
    use sin2A as 2sinAcosA and solve
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Sin2A + sin2B - sin2C = 4cosA*cosB*cosC ...” in 📗 Social Studies if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers