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Blackburn
Social Studies
30 July, 14:13
Sin2A + sin2B - sin2C = 4cosA*cosB*cosC
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Willow Vincent
30 July, 14:21
0
Inconclusive
Explanation:
Sin2A = Sin (A+A) = SinACosA + CosAsinA=2SinACosA
Similarly
Sin2B = 2SinBCosB
Sin2C=2SinCCosC
Adding all; we cannot arrive at the expression at the right.
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Taco
30 July, 14:26
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use sin2A as 2sinAcosA and solve
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