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30 April, 18:33

Maria carries two genes for brown eyes (BB), and John carries two genes for blue eyes (bb). (Assume that BROWN dominates over blue). Their child will have a:

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  1. 30 April, 19:01
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    Their child will have brown eyes because brown allele is dominant.

    Explanation:

    Eye Color

    - Brown eyes B

    - Blue eyes b

    Purebred individual with brown eyes (BB)

    - Homozygous

    Purebred individual with blue eyes (bb)

    - Homozygous

    Hybrid individual with brown eyes (Bb)

    - Heterozygous

    Eye Color

    - Mother is (BB)

    - Father is (bb)

    Their Genes Are Crossed

    - BB x bb

    - Since we are looking at only 1 gene, it is called a monohybrid cross.

    Law of Segregation

    - Alleles for the same trait must be in separate sex cells.

    - Mother is (BB) as his diploid genotype

    - Father is (bb) as her diploid genotype

    Somatic Cells BB bb

    Sex cells B B b b

    So according to the punnett square.

    B b b

    Bb Bb

    B Bb Bb

    Bb shows that the child will have brown eyes as B allele is dominant over b allele.

    Bb = Brown

    All of the offspring will have brown eyes, but they will be heterozygous

    individuals
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