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22 October, 10:33

7. In a certain neighborhood of 100 families, 60 get their news from TV, 54 from the local paper, and 20 from both sources. If a family is selected at random, what is the probability that this family does not use any one of these sources for the news?

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  1. 22 October, 10:53
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    If a family is selected at random, the probability that this family does not get news from either TV or from local paper = 6% or 6/100

    Explanation:

    From the given dа ta:

    The total number = 100

    Families that got their news from TV = 60

    Families that got their news from local paper = 54

    Families that got their news from both TV and local paper = 20

    The probability that family does not use any one of these sources for the news = 1 - probability of the event

    If a family is selected at random, the probability that this family does not use any one of these sources for the news = 1 - (The probability that a selected family get news from either TV or from local paper)

    If a family is selected at random, the probability that this family does not use any one of these sources for the news = 1 - (60/100 + 54/100 - 20/100)

    = 1 - (94/100)

    = 1 - 0.94

    =0.06

    If a family is selected at random, the probability that this family does not get news from either TV or from local paper = 6% or 6/100
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