Ask Question
31 December, 23:10

In a recent year, about 22% of Americans 18 years and older are single. What is the probability that in a random sample of 200 Americans 18 or older more than 30 are single?

+3
Answers (1)
  1. 31 December, 23:18
    0
    Given that p = 0.22, q = 1 - p = 0.78

    n = 200

    mean = miu = np = 200 x 0.22 = 44

    standard deviation = √ (npq) = √ (200 x 0.22 x 0.78) = 5.8583

    P (X>30) = P (X - mean/SD > 30 - 44/5.8583)

    = P (z > - 2.3897)

    = 1 - P (z<-2.3897) = 1 - 0.0084

    = 0.9915

    Hence P (X>30) = 0.9915

    Hence the probability that in a random sample of 200 Americans 18 or older more than 30 are single is 0.9915
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “In a recent year, about 22% of Americans 18 years and older are single. What is the probability that in a random sample of 200 Americans 18 ...” in 📗 Social Studies if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers