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25 February, 06:22

What is the rate of change of the function h (x) = 4x-3 on the interval 0<-x<-1

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  1. 25 February, 06:44
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    - At x = 0

    h (0) = 4 (0) - 3 = - 3

    At x = 1

    h (1) = 4 (1) - 3 = 1

    Rate of change = [1 - (-3) ] / [ '1 - 0 ]

    Rate of change = 4
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