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8 October, 03:24

The gene frequency for a dominant allele is 0.68 and the recessive allele is 0.39. What percent of the population has a homozygous recessive genotype?

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  1. 8 October, 03:30
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    15.21 %

    Explanation:

    If we recall the basic formula of Hardy-Weinberg's equilibrium; we have the following below:

    p + q = 1

    p² + 2pq + q² = 1

    where;

    p = frequency of the dominant allele in the population

    q = frequency of the recessive allele in the population

    p² = percentage of homozygous dominant individuals

    q² = percentage of homozygous recessive individuals

    2pq = percentage of heterozygous individuals

    Given that p = 0.68 and q = 0.39

    the percentage of the homozygous recessive genotype (q²) will be

    (0.39) ² = 0.1521

    = 0.1521 * 100

    = 15.21 %

    ∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %
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