You are conducting a dihybrid cross. You mate a homozygous-dominant-smooth homozygous-recessive-green pea plant (SSyy) with a heterozygous-smooth homozygous-dominant-yellow pea plant (SsYY). What is the likelihood of obtaining an offspring with the following genotype: SSYy? Note: SS and Ss will result in the smooth phenotype; ss will result in the wrinkled phenotype; YY and Yy will result in the yellow phenotype; yy will result in the green phenotype. Hint: you are crossing the following: SSyy X SsYY. What is the likelihood of getting the following: SSYy?

Question

Mary Duffy

Biology

5 July, 22:00

You are conducting a dihybrid cross. You mate a homozygous-dominant-smooth homozygous-recessive-green pea plant (SSyy) with a heterozygous-smooth homozygous-dominant-yellow pea plant (SsYY). What is the likelihood of obtaining an offspring with the following genotype: SSYy? Note: SS and Ss will result in the smooth phenotype; ss will result in the wrinkled phenotype; YY and Yy will result in the yellow phenotype; yy will result in the green phenotype. Hint: you are crossing the following: SSyy X SsYY. What is the likelihood of getting the following: SSYy?

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Answers (1)

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Natasha Palmer · Answer 1

8/16 or 50% is the likelihood of getting SSYy.

Explanation:

To predict the outcome of the occurrence of SSYy, let's make a punnet square:

SY SY sY sY

Sy SSYy SSYy SsYy SsYy

Sy SSYy SSYy SsYy SsYy

Sy SSYy SSYy SsYy SsYy

Sy SSYy SSYy SsYy SsYy

8/16 of the plants will have a chance of having the genotype: SSYy This means that the there will be a 50% chance that the genotype of the offspring will be SSYy.