1. If the frequency of two alleles in a gene pool is 90% A and 10% a, what is the frequency of individuals in the population with the genotype Aa?

Answer: 0.18

Explanation:

For the alleles, the percentage distribution of each is 'A' (90% = 0.9)

While 'a' (10% = 0.1)

Hence, 0.9 and 0.1 are the respective frequencies of each allele

Now, apply Hardy-Weinberg Equilibrium equation, where heterozygotes are represented by the 2pq term.

Therefore, the number of heterozygous individuals (Aa) is equal to 2pq which equals

2 * 0.9 * 0.1 = 0.18

Thus, the frequency of heterozygote is 0.18, while the percentage distribution in the population is 18%