A man and a woman are both carriers of sickle-cell anemia. the man is color blind. the woman is not color blind, nor is she a carrier of color blindness. what proportion of their children who will be carriers of color blindness will also have sickle-cell anemia?

Question

Ashanti Gregory

Biology

19 October, 11:31

A man and a woman are both carriers of sickle-cell anemia. the man is color blind. the woman is not color blind, nor is she a carrier of color blindness. what proportion of their children who will be carriers of color blindness will also have sickle-cell anemia?

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Answers (2)

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Haven Gallegos · Answer 1

If sickle-cell anemia is represented by aa, then it is a recessive trait. Therefore, the man and woman's alleles would be Aa, heterzygous dominant, meaning they are carriers for the disease. If the man is color blind, his alleles would be, let's just say, cc. The woman's would be CC, since she is homozygous dominant. There is a 100% chance that their children will be carriers of color blindness due to the allele combinations. There is a 50% chance that these children will have sickle cell anemia and a 50% chance that these children will carry sickle cell anemia.

Damaris Cohen · Answer 2

If sickle-cell anemia is represented by aa, then it is a recessive trait. Therefore, the man and woman's alleles would be Aa, heterzygous dominant, meaning they are carriers for the disease. If the man is color blind, his alleles would be, let's just say, cc. The woman's would be CC, since she is homozygous dominant. There is a 100% chance that their children will be carriers of color blindness due to the allele combinations. There is a 50% chance that these children will have sickle cell anemia and a 50% chance that these children will carry sickle cell anemia.