The potential difference across a resting neuron in the human body is about 70 mv, and the current in it is approximately 200ua. how much power does the neuron release

I = 200 ua

V = 70 mV

Power = ?

Formula: Power = IV

Solution:

Power = IV

= (200 x 10^-6 A) x (70 x 10^-3 V)

Power = 1.4 x 10^-5 Watts

The power that the neuron release is 1.4 x 10^-5 Watts