Assuming that coleman? s hypotheses about the ob and db genes are correct, rank the mice by the amount of appetite-suppressing hormone you would expect to find circulating in their blood. place the mouse with the lowest hormone level on the left and the mouse with the highest hormone level on the right.

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Glenn Mathews

Biology

9 January, 10:08

Assuming that coleman? s hypotheses about the ob and db genes are correct, rank the mice by the amount of appetite-suppressing hormone you would expect to find circulating in their blood. place the mouse with the lowest hormone level on the left and the mouse with the highest hormone level on the right.

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Jaquan Ortiz · Answer 1

Coleman hypothesized that the product of the ob + gene was the appetite-suppressing hormone. Therefore, the homozygous ob/ob mutant would be unable to synthesize that hormone, and its circulating level would be zero. Coleman also hypothesized that the product of the db + gene was the the receptor for the appetite-suppressing hormone. Therefore, the homozygous db? db mutant would be able to respond to it. It would eat excessively and produce large amounts of body fat, which in turn would produce large amounts of appetite-suppressing hormone. In the absence of a receptor, the db/db mutant's hormone level would remain abnormally high.

Both the ob/ob mutant and the db/db mutant are obese because neither is capable of suppressing its appetite. The ob/ob mutant produces no appetite suppressing hormone and so eats excessively. The db/db mutant cannot respond to the appetite-suppressing hormone and therefore eats excessively.