A scientist is studying two traits in a type of beetle: body texture and color. Smooth body (B) is dominant to bumpy body (b), and gray (G) is dominant to white (g). A BbGg and a bbgg beetle mate and produce the following offspring: Number of Offspring Phenotype 345 Smooth, gray355 Bumpy, white 188 Smooth, white152 Bumpy, grayWhat is the percent recombination frequency for this cross?

Question

Jesse Lutz

Biology

4 March, 14:31

A scientist is studying two traits in a type of beetle: body texture and color. Smooth body (B) is dominant to bumpy body (b), and gray (G) is dominant to white (g). A BbGg and a bbgg beetle mate and produce the following offspring: Number of Offspring Phenotype 345 Smooth, gray355 Bumpy, white 188 Smooth, white152 Bumpy, grayWhat is the percent recombination frequency for this cross?

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Answers (1)

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Brendon Nicholson · Answer 1

32.692%

Explanation:

Recombination frequency = total number of recombinant phentoype in the population / total population size x 100

The heterozygous parent BbGg would form two types of recombinant gametes and two types of parental gametes. The recombinant gametes would carry the allele Bg (smooth and white) and bG (bumpy and gray).

Total recombinant phenotypes in the given progeny = 188 Smooth, white + 152 Bumpy, gray = 188 + 152 = 340

Total population size = 345 Smooth, gray + 355 Bumpy, white + 188 Smooth, white + 152 Bumpy, gray = 345 + 355 + 188 + 152 = 1040

Recombination frequency = 340/1040 x 100 = 32.692%