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15 July, 11:38

What is the entropy change for freezing 2.71 g of C2H5OH at 158.7 K? ∆H = - 4600 J/mol. Answer in units of J/K.

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  1. 15 July, 11:54
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    -1.71 J/K

    Explanation:

    To solve this problem we use the formula

    ΔS = n*ΔH/T

    Where n is mol, ΔH is enthalpy and T is temperature.

    ΔH and T are already given by the problem, so now we calculate n:

    Molar Mass C₂H₅OH = 46 g/mol

    2.71 g C₂H₅OH : 46g/mol = 0.0589 mol

    Now we calculate ΔS:

    ΔS = 0.0589 mol * - 4600 J/mol / 158.7 K

    ΔS = - 1.71 J/K
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