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15 July, 09:28

Assuming an equal mass of nitrogen in each compound, which oxide of nitrogen contains the greatest number of moles of oxygen atoms? N2O3N2O5NO2NO

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  1. 15 July, 09:29
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    N₂O₅

    Explanation:

    To compare the number of moles of oxygen atoms, we will refer them to the same mass (1 g) of N.

    N₂O₃

    In 1 mole of N₂O₃ we have 3 moles of atoms of O.

    In 1 mole of N₂O₃ we have 28 g of N.

    The ratio moles of O:mass of N is 3 mol O : 28 g N = 0.11 mol O : 1 g N

    N₂O₅

    In 1 mole of N₂O₅ we have 5 moles of atoms of O.

    In 1 mole of N₂O₅ we have 28 g of N.

    The ratio moles of O:mass of N is 5 mol O : 28 g N = 0.18 mol O : 1 g N

    NO₂

    In 1 mole of NO₂ we have 2 moles of atoms of O.

    In 1 mole of NO₂ we have 14 g of N.

    The ratio moles of O:mass of N is 2 mol O : 14 g N = 0.14 mol O : 1 g N

    NO

    In 1 mole of NO we have 1 mole of atoms of O.

    In 1 mole of NO we have 14 g of N.

    The ratio moles of O:mass of N is 1 mol O : 14 g N = 0.07 mol O : 1 g N

    N₂O₅ is the one with the greatest number of moles of oxygen atoms per gram of N.
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