Ask Question
26 June, 05:22

What is the empirical formula of a substance that is 53.5% C, 15.5% H, 31.1% N?

+3
Answers (1)
  1. 26 June, 05:35
    0
    For each carbon, hydrogen and nitrogen. You have to divide each percentage by its atomic mass.

    C = 53.5/12.0107 = 4.45436

    H = 15.5/1.00794 = 15.377899

    N = 31.1/14.0067 = 2.220365

    Round the number to significant figures

    C = 4.45

    H = 15.4

    N = 2.22

    Divide Each Number by the smallest number out of the three

    so N = 2.22/2.22 = 1

    H = 15.4/2.22 = 6.9 = 7

    C = 4.45/2.22 = 2

    So the Formula Should Be C2H7N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the empirical formula of a substance that is 53.5% C, 15.5% H, 31.1% N? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers