is first order in NO2 and first order in F2. If the concentration of NO2 was increased by half and the concentration of F2 was increased by four, by what factor would the reaction rate increase?

New rate becomes 7.5 times the original rate and increases by 6.5 times.

Explanation:

According to the law of mass action:-

The rate of the reaction is directly proportional to the active concentration of the reactant which each are raised to the experimentally determined coefficients which are known as orders. The rate is determined by the slowest step in the reaction mechanics.

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

Given that : - Both NO₂ and F₂ are in first order. So,

Rate, r = [NO₂][F₂]

If concentration of NO₂ was increased by half. So, new concentration is : - 1.5 [NO₂]

If concentration of NO₂ was increased by four. So, new concentration is : - 5 [F₂]

New rate, r' = 1.5 [NO₂] x 5 [F₂] = 7.5 [NO₂][F₂] = 7.5 r

It becomes 7.5 times the original rate and increases by 6.5 times.