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10 January, 05:22

How many grams of lithium nitride needs to react with excess water at stp to produce 15.0 l of ammonia

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  1. 10 January, 05:35
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    Mass = 24.4 g

    Explanation:

    Given dа ta:

    Mass of lithium nitride needed = ?

    Volume of ammonia = 15.0 L

    Solution:

    Chemical equation:

    Li₃N + 3H₂O → NH₃ + 3LiOH

    One mole = 22.414 L

    We will compare the volume of lithium nitride and ammonia.

    NH₃ : Li₃N

    22.414 : 22.414

    15.0 : 15.0

    Number of moles of lithium nitride:

    PV = nRT

    n = 1 atm * 15 L / 0.0821 atm. L / mol. K * 273 K

    n = 15 / 22.41 / mol

    n = 0.7

    Mass of Lithium nitride:

    Mass = number of moles * molar mass

    Mass = 0.7 mol * 34.83 g/mol

    Mass = 24.4 g
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