Calculate the volume in liters of a 1.8M sodium chloride solution that contains 175. g of sodium chloride (NaCI). Round your answer to 2 significant digits.

The volume of the NaCl solution is 1.7 L

Explanation:

Step 1: Data given

Molarity of sodium chloride = 1.8 M

Mass of sodium chloride = 175 grams

Molar mass of sodium chloride = 58.44 g/mol

Step 2: Calculate moles sodium chloride

Moles NaCl = mass NaCl / molar mass NaCl

Moles NaCl = 175.0 grams / 58.44 g/mol

Moles NaCl = 2.995 moles

Step 3: Calculate volume of solution

Molarity = moles / volume

Volume = moles NaCl / molarity

Volume = 2.995 moles / 1.8 M

Volume = 1.66 L ≈ 1.7 L

The volume of the NaCl solution is 1.7 L

The volume of sodium chloride is 1.7 liters

Explanation:

Molarity = number of moles/volume

Volume = number of moles/molarity

number of moles of NaCl = mass/MW = 175/58.5 = 2.99mole

Molarity = 1.8M (1.8mole/liter)

Volume = 2.99mole/1.8mole/liter = 1.7 liters (to 2 significant figure)