For the reaction co (g) + 2h2 (g) ch3oh (g) at 700. k, equilibrium concentrations are [h2] = 0.072 m, [co] = 0.020 m, and [ch3oh] = 0.030 m. calculate k

Question

Emelia Sandoval

Chemistry

29 September, 19:03

For the reaction co (g) + 2h2 (g) ch3oh (g) at 700. k, equilibrium concentrations are [h2] = 0.072 m, [co] = 0.020 m, and [ch3oh] = 0.030 m. calculate k

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Moriah Costa · Answer 1

The balanced equation for the reaction is

CO (g) + 2H₂ (g) ⇄ CH₃ OH (g)

Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as

k = [ CH₃OH (g) ] / [CO (g) ] [H₂ (g) ]²

By substitution,

k = 0.030 M / 0.020 M x (0.072 M) ²

k = 289.35 M⁻²