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2 August, 23:46

A chemist places 10.0 grams of dry ice (CO 2) in a 2.5 L vacuum at 25˚C.

After it all sublimates, what would be the pressure inside the container?

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  1. 3 August, 00:02
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    P = 2.25 atm

    Explanation:

    Given dа ta:

    Mass of dry ice = 10 g

    Volume of container = 2.5 L

    Temperature = 25°C (25+273=298 K)

    Pressure inside container = ?

    Solution:

    First of all we will calculate the number of moles of dry ice.

    Number of moles = mass / molar mass

    Number of moles = 10 g / 44 g/mol

    Number of moles = 0.23 mol

    Now we will determine the pressure.

    PV = nRT

    P = nRT/V

    P = 0.23 mol * 0.0821 atm. L/mol. K * 298 K / 2.5 L

    P = 5.63 atm / 2.5

    P = 2.25 atm
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