1. Calculate the [H] in a solution that has a pH of 9.88.

A) 4.1 M

B) 9.9 M

C) 7.6 x 10'M

D) 1.3 x 10 "M

E) none of these

Question

Alan Campos

Chemistry

10 April, 23:19

1. Calculate the [H] in a solution that has a pH of 9.88.

A) 4.1 M

B) 9.9 M

C) 7.6 x 10'M

D) 1.3 x 10 "M

E) none of these

+5

Answers (2)

Know the Answer?

Jovani Haley · Answer 1

The answer to your question is the letter D) [H⁺] = 1.3 x 10⁻¹⁰ M

Explanation:

Data

[H⁺] = ?

pH = 9.88

pH measures the [H⁺] in a solution. It has a range from 0 to 14. Acids have a pH from 0 to 6.9, a neutral solution has a pH of 7.0 and alkalis have a pH from 7.1 to 14.

Formula

pH = - log [H⁺]

Substitution

9.88 = - log[H⁺]

Simplification

antilog - 9.88 = [H⁺]

-Result

[H⁺] = 1.3 x 10⁻¹⁰ M

Joslyn Nelson · Answer 2

Joslyn Nelson 10 April, 23:45

0

The answer to the question is D.

1. Calculate the [H] in a solution that has a pH of 9.88.A) 4.1 MB) 9.9 MC) 7.6 x 10'MD) 1.3 x 10 "ME) none of these

1. Calculate the [H] in a solution that has a pH of 9.88.

A) 4.1 M

B) 9.9 M

C) 7.6 x 10'M

D) 1.3 x 10 "M

E) none of these