Mass box A = 10 grams; Mass box B = 5 grams; Mass box C-made of one A and one B

How much A and B would be needed to produce 30 grams of C? g of A; g of B.

Mass box A = x = 10 grams

Mass box B = y = 5 grams

Both together = 10 + 5 grams = 15 grams

Let the mass of the box C be z.

Mass box C contains One mass box A + one mass Box B.

i. e.,

z = x + y

Given z = 30 grams

For, x = 10 and y = 5

30 = 10 + 5

30 = 15

Unbalanced.

For, x = 20 and y = 10

30 = 2 (10) + 2 (5)

30 = 20 + 10

30 = 30

Balanced.

30grams = 20grams + 10 grams

So, 20 g of A and 10g of B would be needed to produce 30 grams of C (Answer)

2 boxes of A and 2 boxes of B will make 30 grams of C.