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21 November, 01:03

A 10-gram sample of zinc loses 560 J of heat and has a final temperature of 100

degree Celsius. What was its initial temperature?

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Answers (1)
  1. 21 November, 01:11
    0
    Initial temperature is 243.59°C

    Explanation:

    The quantity of heat is calculated by multiplying the mass of a substance by its specific heat capacity and change in temperature.

    That is; Q = m*c*ΔT

    In this case;

    Quantity of heat = 560 J

    Mass of the Sample of Zinc = 10 g

    Final temperature = 100°C

    We are required to determine the initial temperature;

    This can be done by replacing the known variables in the formula of finding quantity of heat,

    Specific heat capacity, c, of Zinc = 0.39 J/g.°C

    Therefore,

    560 J = 10 g * 0.39 J/g°C * ΔT

    ΔT = 560 J : (3.9 J/°C)

    = 143.59°C

    But, since the sample of Zinc lost heat then the temperature change will have a negative value.

    ΔT = - 143.59°C

    Then,

    ΔT = T (final) - T (initial)

    Therefore,

    T (initial) = T (final) - ΔT

    = 100°C - (-143.59°C)

    = 243.59°C

    Hence, the initial temperature of zinc sample is 243.59°C
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