What is the concentration of a CaBr2 solution if 125.00 g of solute was dissolved in enough water to form 250. ml of solution?

2.50M

Explanation:

Concentration of a solution describes how much of a solute is dissolved in a solvent in a solution. Molarity of a solution is one way to calculate the concentration of a solution.

The Molarity, M is calculated using the formula: number of moles (n) / volume of solution (litres).

To calculate, the number of moles (n), we say that number of moles = mass of solute / molar mass

In this case, CaBr2 (Calcium Bromide) solution is used where mass no of Calcium (Ca) is 40g/mol and Bromine (Br) is 79.9g/mol

Molar mass of CaBr2 = 40 + 79.9 (2)

40 + 159.8 = 199.8

Hence, molar mass of CaBr2 is 199.8g/mol

Mass of solute = 125grams

Number of moles (n) of CaBr2 = 125/199.8 = 0.6256

n = 0.6256moles

Volume of CaBr2 solution is 250millilitres (ml). Since, 1000ml = 1L, then 250ml is 250/1000 L

= 0.25L

Molarity of solution (M) = number of moles (n) / volume of solution (litres)

M = 0.6256/0.25

M = 2.5

Thus, the molarity (concentration) of the solution is 2.5M