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8 December, 03:12

According to the following reaction, how many grams of hydrogen peroxide (

H

2

O

2

) are necessary to form 0.182 moles oxygen gas?

hydrogen peroxide (

H

2

O

2

) (aq)



water (l) + oxygen (g)

+4
Answers (1)
  1. 8 December, 03:26
    0
    12.4 g

    Explanation:

    Let's consider the following balanced equation.

    H₂O₂ (aq) → H₂O (l) + 0.5 O₂ (g)

    The molar ratio of H₂O₂ to O₂ is 1:0.5. The moles of H₂O₂ required to form 0.182 moles of O₂ are:

    0.182 mol O₂ * (1 mol H₂O₂ / 0.5 mol O₂) = 0.364 mol H₂O₂

    The molar mass of H₂O₂ is 34.01 g/mol. The mass of H₂O₂ corresponding to 0.364 moles is:

    0.364 mol * 34.01 g/mol = 12.4 g
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