How much heat is added if 0.2067g of water is increased in temperature by 0.855

degrees C?

0.756 J

Explanation:

Temperature change (delta T) = 0.855 degrees Celsius

Mass of water (m) = 0.2067 g

Specific heat capacity of water (c) = 4.28 J/g degrees C

Heat added = m * c * delta T

= (0.2067 * 4.28 * 0.855) J

= 0.756 J