What is the rate of a reaction if the value of kis 0.1, [A] is 1 M, and [B] is 2 M? Rate = K[A]2[B]2

A. 1.6 (mol/L) / s

B. 0.8 (mol/L) / S

C. 0.2 (mol/L) / S

D. 0.4 (mol/L) / S

Question

Bronson Noble

Chemistry

9 July, 10:53

What is the rate of a reaction if the value of kis 0.1, [A] is 1 M, and [B] is 2 M? Rate = K[A]2[B]2

A. 1.6 (mol/L) / s

B. 0.8 (mol/L) / S

C. 0.2 (mol/L) / S

D. 0.4 (mol/L) / S

+4

Answers (1)

Know the Answer?

Kassandra Ballard · Answer 1

D. 0.4 (mol/L) / S

Explanation:

You simply have to plug in the given values into the rate law.

Rate = k[A][B]

Rate = (0.1) (1) ² (2) ²

Rate = (0.1) (1) ² (4) ²

Rate = 0.4

What is the rate of a reaction if the value of kis 0.1, [A] is 1 M, and [B] is 2 M? Rate = K[A]2[B]2A. 1.6 (mol/L) / sB. 0.8 (mol/L) / SC. 0.2 (mol/L) / SD. 0.4 (mol/L) / S

What is the rate of a reaction if the value of kis 0.1, [A] is 1 M, and [B] is 2 M? Rate = K[A]2[B]2

A. 1.6 (mol/L) / s

B. 0.8 (mol/L) / S

C. 0.2 (mol/L) / S

D. 0.4 (mol/L) / S