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10 December, 11:21

How much NaAlO2 (sodium aluminate) is required to produce 2.15 kg of Na3AlF6?

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  1. 10 December, 11:47
    0
    839 g

    Explanation:

    We know we will need a balanced equation with masses and molar masses, so let's gather all the information in one place.

    M_r: 81.97 209.94

    NaAlO₂ + ... ⟶ Na₃AlF₆ + ...

    Mass/g: 2150

    1. Calculate the moles of Na₃AlF₆

    Moles of Na₃AlF₆ = 2150 * 1/209.94 Do the operation

    Moles of Na₃AlF₆ = 10.24 mol Na₃AlF₆

    2. Calculate the moles of NaAlO₂

    The molar ratio is 1 mol NaAlO₂:1 mol Na₃AlF₆

    Moles of NaAlO₂ = 10.24 * 1/1 = 10.24 mol NaAlO₂

    3. Calculate the mass of NaAlO₂

    Mass of NaAlO₂ = 10.24 * 81.97 Do the multiplication

    Mass of NaAlO₂ = 839 g
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