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26 August, 12:00

Justin added concentrated HCl solution in excess to 45.8 grams of magnesium metal and collected the hydrogen gas that was produced by the reaction.

Mg (s) + 2 HCl (aq) → MgCl2 (aq) + H2 (g)

If Justin collected 2.01 grams of H2, what was the percent yield of H2?

A 4.39%

B 46.9%

C 52.9%

D 93.8%

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Answers (2)
  1. 26 August, 12:07
    0
    I have the same question
  2. 26 August, 12:07
    0
    52.9 %.

    Explanation:

    Mg + 2HCl - --> MgCl2 + H2

    Using the relative atomic masses of magnesium and hydrogen:

    Theoretically 24.3 g of Mg will produce 2.016 g of H2

    so 45.8 g will produce (2.016 * 45.8) / 24.3 = 3.80 g H2.

    So the % yield = 2.01 * 100 / 3.80

    = 52.9%.
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