The first ionization energy of polonium, Po, is 812 kJ/mol. Is the first ionization energy of Lv expected to be greater than, less than, or equal to that of Po? Justify your answer in terms of Coulomb's law.

Question

Malachi Nunez

Chemistry

11 March, 14:41

The first ionization energy of polonium, Po, is 812 kJ/mol. Is the first ionization energy of Lv expected to be greater than, less than, or equal to that of Po? Justify your answer in terms of Coulomb's law.

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Answers (1)

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Colten Norman · Answer 1

The first ionization energy comparison between Lv and Po can be justified using Coulomb's law.

Explanation:

The two atoms (Lv and Po) have comparable effective nuclear charges but the valence electron in Lv would be at the greater distance from the nucleus than those in Po. By Coulomb's law, the attractive forces between the valence electron and the nucleus decrease by the inverse square of the distance between them.