A5.00 liter ballon of gas at 25 degree Celsius is cool to 0 degrees Celsius. What is the volume (liters) of the ballon?

The new volume is 4.58L

Explanation:

Let's apply the Charles Gay Lussac law for this, where the volume is modified directly proportional to absolute T° (T° in K)

25°C + 273 = 298K

0°C + 273 = 273K

V₁ / T₁ = V₂ / T₂

5L / 298K = V₂ / 273K

(5L / 298K). 273K = V₂

In this case, as the temperature has been decreased, the volume also decreased.