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11 September, 23:08

If one antacid tablet contains 0.10g of Magnesium hydroxide how many grams of stomach acid does this tablet neutralize?

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  1. 11 September, 23:10
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    0.1252 g of HCl

    Explanation:

    Antacid acts to neutralize excessive acid in the stomach.

    The stomach contains hydrochloric acid, HCl.

    Therefore; a reaction of antacid (magnesium hydroxide) and HCl will be;

    Mg (OH) ₂ (s) + 2HCl (aq) → MgCl₂ (aq) + 2 H₂O (l)

    We are given;

    Mass of magnesium hydroxide as 0.10 g

    We can calculate the mass of HCl neutralized by the acid using the following simple steps;

    Step 1 : Number of moles of Mg (OH) ₂

    Number of moles is calculated by dividing the mass of a compound with the relative formula mass of the compound.

    Relative formula mass of the compound = 58.32 g/mol

    Therefore;

    Number of moles of Mg (OH) ₂ = 0.10 g : 58.32 g/mol

    = 0.001715 mol

    Step 2: Number of moles of HCl neutralized by 0.10 g of Mg (OH) ₂

    Moles of Mg (OH) ₂ = 0.001715 mol

    But, from the equation 1 mole of Mg (OH) ₂ reacts with 2 moles of HCl

    Thus;

    0.001715 moles Mg (OH) ₂ will neutralize;

    = 0.001715 * 2

    = 0.003430 moles HCl

    Step 3: Mass of HCl neutralized

    Mass is calculated by multiplying the number of moles by the relative formula mass of a compound.

    Molar mass of HCl = 36.5 g/mol

    Therefore;

    Mass = 0.003430 mol * 36.5 g/mol

    = 0.1252 g HCl

    Therefore; 0.10 g of Mg (OH) ₂ neutralizes 0.1252 g of HCl
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