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5 April, 10:15

How much heat is required to vaporize 25g of water at 100*c

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  1. 5 April, 10:36
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    Heat required = 13,325 calories or 55.75 KJ.

    Explanation:

    To convert a water to steam at 100 degree celsius to vapor, we have to give latent heat of vaporization to water

    Which equals,

    Q = mL,

    Where, m is the mass of water present

    L = specific latent heat of vaporization

    Here, m = 25 gram

    L equals to 533 calories (or 2230 Joules)

    So, Q = 25*533 = 13,325 Calories

    Or, Q = 55,750 Joules = 55.75 KJ

    so, Heat required = 13,325 calories or 55.75 KJ.
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