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30 April, 05:21

A gas sample occupies 5.38L at 36.0C. what is its temperature if volume is changed to 4.86L

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  1. 30 April, 05:22
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    Answer: 2.5°C

    Explanation:

    Initial volume V1 = 5.38 liters

    Initial temperature T1 = 36.0°C

    Convert temperature in Celsius to Kelvin

    (32°C + 273 = 305K)

    Final temperature T2 = ?

    Final volume V2 = 4.68 liters

    According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

    Thus, Charles' Law is expressed as: V1/T1 = V2/T2

    5.38/305 = 4.86/T2

    To get the value of T2, cross multiply

    5.38 x T2 = 4.86 x 305

    5.38T2 = 1482.3

    Divide both sides by 5.38

    5.38T2/5.38 = 1482.3/5.38

    T2 = 275.5K

    Convert 275.5K to Celsius

    (275.5K - 273K = 2.5°C)

    Thus, the final temperature is 2.5°C
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