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29 April, 23:52

What is the volume of a gas at 90 degrees celsius, if it occupies 1.41L at 170 degrees celsius

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  1. 30 April, 00:11
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    Answer: 1.15 L

    Explanation:

    Working under the assumption that this takes place at constant pressure, Charles Law; V1 / T1 = V2/T2 would be applied.

    V1 = Initial Volume = 1.41L

    V2 = Final Volume = ?

    T1 = Initial Temperature = 170 ° C, which is (273.15 + 170) K = 443.15K

    T2 = Final Temperature = 90 ° C, which is (273.15 + 90) K = 363.15K

    ∴ Making V2 subject of the formular, we then have;

    V2 = V1 x T2 / T1 = 1.4L x 363.15K / 443.15K

    = 508.41 / 443.15 = 1.15 L
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