Iron has a mass of 7.87 g per cubic centimeter of volume, and the mass of an iron atom is 9.27 * 10-26 kg. If you simplify and treat each atom as a cube, (a) what is the average volume (in cubic meters) required for each iron atom and (b) what is the distance (in meters) between the centers of adjacent atoms?

(a) what is the average volume (in cubic meters) required for each iron atom

For this case, the density of Iron would be 7.87g/cm³

V = 9.27 x 10^-26 kg / 7.87g/cm ³ (1 kg / 1000 g)

V = 1.18 x 10-23 cm³

(b) what is the distance (in meters) between the centers of adjacent atoms?

We assume the atoms as cube, so we use the volume of the cube to calculate the distance of the atoms.

V = 1.18 x 10-23 cm ³ = s ³

s = 2.28 x 10^-8 cm