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14 March, 08:28

Consider the reaction: HCl (aq) + NaOH (aq) → NaOH (aq) + H2O (l) How much 0.113 M NaOH solution will completely neutralize 1.25 L of 0.228 M HCl solution?

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  1. 14 March, 08:46
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    1.25L Hcl (.228 mol HCl/1 L) = 0.285 mol HCl

    0.285 mol HCl (1 mol NaOH/1 mol HCl) = 0.285 mol NaOH

    0.285 mol NaOH (1 L/.113 mol NaOH) = 2.52212 L of. 113M NaOH solution
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