A solution was prepared by dissolving 193 mg of potassium sulfate (K2SO4, MW = 174.24 g/mol) in 603 mL of water. Use this information to calculate each quantity.

Question

Krish Washington

Chemistry

13 February, 06:04

A solution was prepared by dissolving 193 mg of potassium sulfate (K2SO4, MW = 174.24 g/mol) in 603 mL of water. Use this information to calculate each quantity.

+1

Answers (1)

Know the Answer?

Michaela · Answer 1

C K2SO4 = 1.837 E-3 M

Explanation:

K2SO4 (s) + H2O (l) ↔ 2K + (aq) + SO42 - (aq)

∴ m K2SO4 = 193 mg * (g / 1000 mg) = 0.193 g

∴ Mw K2SO4 = 174.24 g/mol

∴ Vsln = 603 mL H2O = 0.603 L sln

⇒ mol K2SO4 = 0.193 g * (mol / 174.24 g) = 1.108 E-3 mol

⇒ C K2SO4 = 1.108 E-3 mol / 0.603 L = 1.837 E-3 M