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16 August, 23:47

what temperature will 215 mL of a gas at 20°C and 1 atm pressure attain when it is subject to 1.5 atm of pressure?

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  1. 16 August, 23:50
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    Given:

    Volume of gas = 215 ml

    Initial temperature T1 = 20C = 20 + 273 = 293 K

    Initial pressure P1 = 1 atm

    Final pressure P2 = 1.5 atm

    To determine:

    The final temperature T2

    Explanation:

    Based on Gay-Lussac's Law:

    P α T

    Therefore we have the relation:

    P1/T1 = P2/T2

    T2 = P2T1/P1 = 1.5 * 293/1 = 439.5 K

    Converting from Kelvin to degrees C we have:

    T2 = 439.5 - 273 = 166.5 C

    Ans: The final temperature is 439.5 K or 166.5 C
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